The electrophile involved in the reaction shown below is:
$C_6H_5OH + CHCl_3 + NaOH \rightarrow C_6H_4(ONa)CHO$
$C_6H_5OH + CHCl_3 + NaOH \rightarrow C_6H_4(ONa)CHO$
- Adichlorocarbene $(:CCl_2)$
- Btrichloromethyl anion $(\mathop{C}\limits^{\ominus}Cl_3)$
- Cformyl cation $(\mathop{C}\limits^{\oplus}HO)$
- Ddichloromethyl cation $(\mathop{C}\limits^{+}HCl_2)$
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